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CardName: Flip out Cost: {X}{R} Type: Sorcery Pow/Tgh: / Rules Text: Each opponent flips X coins. If more than 6 are tails, they lose the game. Flavour Text: Using this as the finisher for an uncountable mana combo is considered cruel - but you'll still win once you get them cautioned for timewasting. Set/Rarity: My Universe, My Rules Mythic

Flip out
{x}{r}
 
 M 
Sorcery
Each opponent flips X coins.
If more than 6 are tails, they lose the game.
Using this as the finisher for an uncountable mana combo is considered cruel – but you'll still win once you get them cautioned for timewasting.
Updated on 26 Feb 2014 by Vitenka

Code:

History: [-]

2014-02-26 15:43:18: Vitenka created the card Flip out

Alternate title: "Table Flip".

10/10 would play.

2014-02-26 16:07:21: Vitenka edited Flip out:

yeah, 3 is too low. Let's double that.

Interestingly, the CR allows for the coin not being a coin - "705.3 ... Other methods of randomization may be substituted for flipping a coin as long as there are two possible outcomes of equal likelihood and all players agree to the substitution..."

What's not clear is whether you can substitute for the whole series. Am I allowed, for instance, to ask random.org or invisiblecastle.com to roll that many 2-sided dice? Or Wolfram Alpha to "sample binomial(1000,0.5)"?

I assume you could roll a whole series under 705.3, as in substituting each flip for the corresponding virtual d2.

You might not technically be allowed to simulate them with a single result value, since theoretically the result of each individual die is public knowledge. But assuming there aren't any "care about how many flips you win" cards in play, I think it would be OK in practice.

Similar questions have occasionally come up on the judges list. You can get situations like where a player has an unbounded mana combo, a Whetstone and a single Limestone Golem, and the opponent has an Emrakul, the Aeons Torn in their library and an odd number of total cards in library-and-graveyard (say 41). So each time through the opponent's library, it will trigger a reshuffle when the Emrakul is hit. The infinite-mill player can win as long as they can force the opponent to draw the Emrakul, but they can only do that if they mill all 40 other cards. They would like to shortcut the mill-and-reshuffle as many times as they'd like, each time Emrakul is in position 1-40, and skip to the situation where Emrakul is in position 41. I believe the last ruling I saw on that was that nondeterministic shortcuts are not allowed, so tough luck Mr Infinite-Mill, you should have played a Braingeyser.

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