So Ling 素靈: Cardlist | Visual spoiler | Export | Booster | Comments | Search | Recent activity
Mechanics | Skeleton | So Ling Block Overview | Planeswalker's Guide to So Ling 素靈

CardName: Bob // Weave Cost: ? b // ? ww Type: Sorcery // Sorcery Pow/Tgh: / // / Rules Text: ({?} can be paid with either {2} or 2 life.) Reveal the top card of your library and put that card into your hand. You lose life equal to its converted mana cost. You may repeat this process two times. Fuse (You may cast one or both halves of this card from your hand.) // ({?} can be paid with either {2} or 2 life.) Put up to one enchantment card from your hand onto the field. Flavour Text: Set/Rarity: So Ling 素靈 Uncommon

Bob
{?} {b}
 
 U 
Sorcery
({?} can be paid with either {2} or 2 life.)

Reveal the top card of your library and put that card into your hand. You lose life equal to its converted mana cost. You may repeat this process two times.

Fuse (You may cast one or both halves of this card from your hand.)
Weave
{?} {w}{w}
 
 U 
Sorcery
({?} can be paid with either {2} or 2 life.)

Put up to one enchantment card from your hand onto the field.
Updated on 20 Aug 2020 by amuseum

Code:

History: [-]

2013-10-09 07:43:04: amuseum created and commented on the card Bob // Weave

probably for next set

2013-10-09 07:45:25: amuseum edited Bob // Weave

bwahaha, "Bob" :D

Awww. It's a sorcery. No "summon Bob"

Nice card though; kinda odd to combine them though - you want to put a really expensive enchantment into play with it; but you sure don't want to draw it!

V: It's a reference to Dark Confidant, which was designed by Bob Maher and is known as Bob pretty much universally. Turning his effect into a one-off spell that's half of Bob // Weave is a stroke of genius :)

2013-10-09 23:32:32: amuseum edited Bob // Weave
2016-10-10 04:08:37: amuseum edited Bob // Weave
2020-07-16 03:21:46: amuseum edited Bob // Weave
2020-08-20 03:35:18: amuseum edited Bob // Weave

Only signed-in users are permitted to comment on this cardset. Would you like to sign in?