CardName: Sarkhan's Beckoning
Cost: 3RRBB
Type: Instant
Pow/Tgh: /
Rules Text: Put a dragon from your hand onto the battlefield; then deal
X damage to target player and each creature he or she
controls; then put up to X 5/5 dragon creature tokens with
flying onto the battlefield; then destroy up to X target
creatures. X is equal to the number of dragons you control.
Flavour Text:
Set/Rarity: Warbreak Rare
Sarkhan's Beckoning
R
Instant
Put a dragon from your hand onto the battlefield; then deal X damage to target player and each creature he or she controls; then put up to X 5/5 dragon creature tokens with flying onto the battlefield; then destroy up to X target creatures. X is equal to the number of dragons you control.
How are the numbers on this meant to work? Suppose I control 2 Dragons before it resolves. I cast it, choosing targets of Player B, and choosing two target creatures.
When it resolves: First I put a Dragon from hand onto the battlefield. Assuming I don't choose Crib Swap or Nameless Inversion, that'll make me control 3 Dragons. Then is this meant to deal 3 damage to B and all his creatures? Then I get 3 more Dragon tokens, making me control 6 Dragons... and then I get to destroy up to 6 target creatures. But I was only able to choose 2 targets when casting it, so the other 4 "up to" possibilities are wasted? Is that right?
How are the numbers on this meant to work? Suppose I control 2 Dragons before it resolves. I cast it, choosing targets of Player B, and choosing two target creatures.
When it resolves: First I put a Dragon from hand onto the battlefield. Assuming I don't choose Crib Swap or Nameless Inversion, that'll make me control 3 Dragons. Then is this meant to deal 3 damage to B and all his creatures? Then I get 3 more Dragon tokens, making me control 6 Dragons... and then I get to destroy up to 6 target creatures. But I was only able to choose 2 targets when casting it, so the other 4 "up to" possibilities are wasted? Is that right?