Jandora: Cardlist | Visual spoiler | Export | Booster | Comments | Search | Recent activity
Mechanics | Skeleton

CardName: Ghost Bear Cost: {1}{W} Type: Creature - Spirit Beast Pow/Tgh: 2/2 Rules Text: Ritual - {W}{W}, discard a card (You may play this card from your graveyard for its ritual cost .) Flavour Text: Set/Rarity: Jandora Common

Ghost Bear
{1}{w}
 
 C 
Creature – Spirit Beast
Ritual – {w}{w}, discard a card (You may play this card from your graveyard for its ritual cost .)
2/2
Updated on 18 Feb 2016 by Zalabar

Code: CW08

History: [-]

2011-01-04 21:09:42: Zalabar created the card Ghost Bear
2011-01-05 06:38:14: Zalabar edited Ghost Bear

I worry if Ritual might be a bit too much better than Madness.

You pay the ritual cost in addition to its other costs, not instead of like madness (i.e. To play Ghost Bear from your graveyard you would pay {1}{w} and discard a card).

Oh, of course. Sorry. So it's like Retrace as on Flame Jab, but with any card instead of a land.

Yes, and it can go on permanents as well as instants and sorceries. I have tried to make it so either you don't gain card advantage (i.e. You discard a card or sac. something) or the cost is extremely high for the given effect like buyback.

Come to think of it, wouldn't the rules for retrace work equally well on permanents. You might even consider treating it like echo, and retroactively adding a cost to retrace. Although that does make a mess as the default retrace is "retrace discard a card" which looks ugly.

Indeed, retrace could have worked on permanents. Would have been fine on a Grizzly Bear, too.

The problem with retrace is that the cost is always discard a land, and I want to be able to have varied costs. Also, retrace was only ever on instants and sorceries and I think a new keyword should be created for something that works with all card types.

2011-01-17 21:36:47: Zalabar edited Ghost Bear
2015-01-29 19:11:16: Zalabar edited Ghost Bear

Only signed-in users are permitted to comment on this cardset. Would you like to sign in?